1. 設(shè)是
階方陣,
為
的伴隨矩陣,且
,已知齊次線性方程組
有
非零解,則非齊次線性方程組
( ).
A. 無(wú)解 B. 有唯一解
C. 有無(wú)窮多組解 D. 無(wú)法判斷解的情況
2. 下面四個(gè)矩陣中,使成立的矩陣
有( )個(gè).
① ②
③ ④
A. 1 B. 2
C. 3 D. 4
3. 維向量空間
的基
,
到基
,
的過(guò)渡矩陣為( ).
A. B.
C. D.
4. 設(shè)是3階方陣,將
的第1行與第2行交換得
,再把
的第2行加到第3行得
,則
滿足的可逆矩陣
為( ).
A. B.
C. D.
5. 已知,
是矩陣
的屬于特征值3的特征向量,
是矩陣
的屬于特
征值1的線性無(wú)關(guān)的特征向量,則下列矩陣可以是矩陣的是( ).
①. ②
.
③. ④
.
A. ① ③ B. ② ④
C. ② ③ D. ① ②
1.答案:C.解析:本題綜合考查非齊次方程組解的理論.
因?yàn)辇R次線性方程組有非零解
,所以
,又因?yàn)?img height="21" src="data:image/wmf;base64,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" width="44" />,所以
,得
,所以
,因此齊次線性方程組
有無(wú)窮多組解.
又,所以
的
個(gè)線性無(wú)關(guān)的列向量是
的基礎(chǔ)解系,所以
可由
的
個(gè)線性無(wú)關(guān)的列向量線性表示,即
可由
的
個(gè)列向量線性表示,因此非齊次線性方程組
有解,所以C正確.
2.答案:B.解析:本題考查矩陣的運(yùn)算.
要想使矩陣滿足
,則需滿足
.滿足題意的有①②,具體可見(jiàn)紅師教育出品的《戎易學(xué)題庫(kù)》數(shù)學(xué)一專業(yè)
.
3.答案:B.解析:本題考查向量空間下不同基之間的過(guò)渡矩陣.
因?yàn)?img height="42" src="data:image/wmf;base64,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" width="315" />所以.
4.答案:A.解析: 本題考查初等變換與初等矩陣的關(guān)系.
由于,即
,所以
,A正確.
5.答案:A.解析:本題綜合考查特征值與特征向量的性質(zhì).
顯然①正確;在②中,由于,所以②錯(cuò)誤;在③中,
仍是
的屬于特征值1的線性無(wú)關(guān)的特征向量,所以③正確;在④中,因?yàn)?img height="21" src="data:image/wmf;base64,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" width="45" />不是
的特征向量,所以④錯(cuò)誤,答案為A.
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